TSTP Solution File: SYN983^1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN983^1 : TPTP v8.1.2. Released v3.6.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:32 EDT 2023
% Result : Theorem 3.67s 3.84s
% Output : Proof 3.67s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN983^1 : TPTP v8.1.2. Released v3.6.0.
% 0.13/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n003.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 20:25:09 EDT 2023
% 0.20/0.35 % CPUTime :
% 3.67/3.84 SZS status Theorem for theBenchmark.p
% 3.67/3.84 SZS output start Proof for theBenchmark.p
% 3.67/3.84 Clause #0 (by assumption #[]): Eq (Not (And (p a) (p b) → p (And a b))) True
% 3.67/3.84 Clause #1 (by clausification #[0]): Eq (And (p a) (p b) → p (And a b)) False
% 3.67/3.84 Clause #2 (by clausification #[1]): Eq (And (p a) (p b)) True
% 3.67/3.84 Clause #3 (by clausification #[1]): Eq (p (And a b)) False
% 3.67/3.84 Clause #4 (by clausification #[2]): Eq (p b) True
% 3.67/3.84 Clause #5 (by clausification #[2]): Eq (p a) True
% 3.67/3.84 Clause #7 (by identity boolHoist #[4]): Or (Eq (p False) True) (Eq b True)
% 3.67/3.84 Clause #8 (by identity loobHoist #[5]): Or (Eq (p True) True) (Eq a False)
% 3.67/3.84 Clause #9 (by identity boolHoist #[5]): Or (Eq (p False) True) (Eq a True)
% 3.67/3.84 Clause #10 (by identity loobHoist #[3]): Or (Eq (p True) False) (Eq (And a b) False)
% 3.67/3.84 Clause #11 (by identity boolHoist #[3]): Or (Eq (p False) False) (Eq (And a b) True)
% 3.67/3.84 Clause #12 (by clausification #[10]): Or (Eq (p True) False) (Or (Eq a False) (Eq b False))
% 3.67/3.84 Clause #13 (by clausification #[11]): Or (Eq (p False) False) (Eq b True)
% 3.67/3.84 Clause #14 (by clausification #[11]): Or (Eq (p False) False) (Eq a True)
% 3.67/3.84 Clause #15 (by superposition #[13, 7]): Or (Eq b True) (Or (Eq False True) (Eq b True))
% 3.67/3.84 Clause #18 (by superposition #[14, 9]): Or (Eq a True) (Or (Eq False True) (Eq a True))
% 3.67/3.84 Clause #19 (by clausification #[18]): Or (Eq a True) (Eq a True)
% 3.67/3.84 Clause #20 (by eliminate duplicate literals #[19]): Eq a True
% 3.67/3.84 Clause #21 (by backward demodulation #[20, 8]): Or (Eq (p True) True) (Eq True False)
% 3.67/3.84 Clause #22 (by backward demodulation #[20, 12]): Or (Eq (p True) False) (Or (Eq True False) (Eq b False))
% 3.67/3.84 Clause #25 (by clausification #[21]): Eq (p True) True
% 3.67/3.84 Clause #26 (by clausification #[15]): Or (Eq b True) (Eq b True)
% 3.67/3.84 Clause #27 (by eliminate duplicate literals #[26]): Eq b True
% 3.67/3.84 Clause #32 (by clausification #[22]): Or (Eq (p True) False) (Eq b False)
% 3.67/3.84 Clause #33 (by forward demodulation #[32, 27]): Or (Eq (p True) False) (Eq True False)
% 3.67/3.84 Clause #34 (by clausification #[33]): Eq (p True) False
% 3.67/3.84 Clause #35 (by superposition #[34, 25]): Eq False True
% 3.67/3.84 Clause #36 (by clausification #[35]): False
% 3.67/3.84 SZS output end Proof for theBenchmark.p
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